11/19/2023 0 Comments Java to convert string to long![]() if there are any empty spaces also take it out. replace all commas if present with no comma Modifying your example: String s '1333073704000' long l Long. String s = "4,54,8908.90" //String Decleration The method for converting a string to a long is Long.parseLong. Here, a String value is converted into double values taking the commas into consideration. If we want to convert a value that contains commas then use replaceAll() method to replace that commas and the use parseDouble() method to get double value. String s2 = "mohit" //NumberFormatException String s1 = "500.77" //String declarationĭouble i1 = Double.valueOf(s1) // Double.valueOf() method converts a String into Double ![]() ![]() Here, a String value is converted into a double value by using the valueOf() method. This method is used to convert a String into a Double Object. The valueOf() method is a part of Double class. public class StudyTonightĭouble i = Double.parseDouble(s) // Double.parseDouble() converts the string into doubleĤ54.9 2. Here, a String value is converted into double type value by using the parseDouble() method. The input bytes can be entered as a space-separated array or as a long hex number. It is a static method and is used to convert a String into a double. This browser-based program converts bytes to a string. The parseDouble() method is a part of the Double class. Whenever a data(numerical) is received from a TextField or a TextArea it is in the form of a String and if we want double type then it is required to be converted into a double before performing any mathematical operation. Also, a String can be converted into a Double object using the Double.valueOf() method. ![]() matches now contains all Longs found in the stringOf course that would require another iteration to turn the List into a Long or long, but the List should be fine for most cases.īut the initial question was: "How do i convert string array into long array in java?" and that's impossible without a second iteration (I count recursion as iterating in this case).In Java, a String can be converted into a double value by using the Double.parseDouble() method. String match = input.substring(index, matcher.start()) Matcher matcher = pattern.matcher(input) This splitting a string into longs would be something like this (code based on Pattern.split): And I doubt that using a Pattern / Matcher combination would be slower - because that's just what String.split uses - it delegates to Pattern.split which uses a Matcher. I agree that splitting and parsing in one go would remove the need for a second iteration. Now, of course, whether this saves any time, is unclear. Instead of using split(), you can use find(), to get each "long" string element, in order to convert to a long - in one pass. Technically, there is a way to do without iterating through the array - you can skip generating the array in the first place. What you can do is format a long that holds 5 with a leading zero when you print it, see e.g. A string of characters like 05 is not an integer, 5 is. ![]() A long is supposed to store integers (the mathematical concept, not int), i.e. You already iterated once through the string, in order to split it into an array. You cannot because a long does not have a leading zero. Whatever solution you use, in the end you will still need to change each separate string element into a long.Ī more complicated answer. Without iterating the array,Is there is any other way to do it. ![]()
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